" 7."3(t-3)=5(2t+1)

If 3(t-3) = 5(2t + 1) , then t = ?

Solve the following equations : 3 (t-3) = 5 (2t - 1)

In 1/2( t+3)=2( t+ 7) , LHS=_____

Each of four particles moves along an x axis. Their coordinates (in meters) as function of time (in seconds) are given by Particle 1:x(t) =3.5 -2.7t^(3) Particle :2 x(t)=3.5+2.7 t^(3) particle 3: x(t) =3.5+2.7 t^(2) particle 4: x(t)=3.5-3.4 t -2.7 t^(2) Which of these particles have constant acceleration ?

If A=((1,-2),(4,5)) and f(t)=t^(2)-3t+7 then f(A)+((3,6),(-12,-9))=

If x=7/(1+t^3), y=(7t)/(1+t^3) , then show that (dy)/(dx)=(2t^3-1)/(3t^2)

If A=[[1,-24,5]] and f(t)=t^(2)-3t+7 then f(A)+[[3,6-12,-9]]=

if A=[[1,-24,5]] and f(t)=t^(2)-3t+7 then f(A)+[[3,6-12,-9]]=

Solve the equation : (3t+1)/16-(2t-3)/7=(t+3)/8+(3t-1)/14