[" The sect tang= "P],[(p^(2)-1)/(2)=sin theta]

If sin theta+tan theta=P then prove that (p^(2)-1)/(p^(2)+1)=sin theta

If sec theta+tan theta =p then prove that (p^2-1)/(p^2+1)=sin theta

If sec theta+tan theta=p,quad show that (p^(2)-1)/(p^(2)+1)=sin theta

ABCD is a trapezium such that AB and CD are parallel and BC bot CD . If angleADB = theta, BC = p and CD = q , then AB is equal to (a) ((p^(2)+q^(2))sin theta)/(p cos theta +q sin theta) (b) (p ^(2) + q ^(2)cos theta)/(p cos theta +q sin theta) (c) (p ^(2)+ q^(2))/(p^(2)cos theta +q^(2) sin theta) (d) ((p^(2) +q^(2))sin theta)/((p cos theta + sin theta)^(2))

If p tan theta = tan p theta , then show that : (sin^2 p theta)/(sin^2 theta)= (sin p^2)/(1+(p^2-1)sin^2 theta) .

If p tan theta=tan p theta , show that, (sin^2p theta)/(sin^2theta)=(p^2)/(1+(p^2-1)sin^2 theta)

If sin theta=(p^2-1)/(p^2+1) , then cos theta is equal to : यदि sin theta= (p^2-1)/(p^2+1) है, तो cos theta का मान है :

If sec theta + tan theta = p , prove that (i) sec theta =(1)/(2)(p+(1)/(p)) " (ii) "tan theta =(1)/(2)(p-(1)/(p)) " (iii) " sin theta =(p^(2)-1)/(p^(2)+1).

if : p*cos theta=sqrt(p^(2)+q^(2)).sin theta, "then" : q * sin theta=