Home
Class 10
MATHS
Find the equation of the internal bisect...

Find the equation of the internal bisector of angle BAC of the triangle ABC whose vertices A, B, C are (5, 2), (2, 3) and (6, 5) respectively

Text Solution

Verified by Experts

Equation of line AB
`y-2=((3-2)/(2-5))*(x-5)`
`x-3y+1=0-(1)`
Equation of line AC
`y-2=((5-2)/(6-5))(x-5)`
`3x-y-13=0-(2)`
`(ax_1+by_1+c_1)/sqrt(a_1^2+b_1^2)=pm(a_2x+b_2y+c_2)/sqrt(a_2^2+b_2^2)`
`(x-3y+1)/sqrt10=pm(3x-y-13)/sqrt10`
...
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the internal bisector of angle B A C of the triangle A B C whose vertices A ,B ,C are (5,2),(2,3)a n d(6,5) respectively.

Find the equation of the bisector of angle A of triangle ABC , whose vertices are A(-2,4), B(5,5) and C(4,-2) .

Find the equation of the bisector of angle A ofthe triangle whoe vertices are A(4,3),B(0,0) and C(2,3)

Find the equation of the bisector of angle A of DeltaABC whose vertices are A(-2, 4), B(5,5) and C(4,-2) is

Find the equation of bisector of angleA of triangleABC whose vertices are A(-2,4),B(5,5) and C(4,-2) .

Find the equation of the medians of the triangle ABC whose vertices are A(2,5)B(-4,9) and C(-2,-1)

The equation of the altitude of the triangle ABC whose vertices are A(-4,2), B(6,5) and C(1,-4) can be

Find the area of triangle ABC whose vertices are A(-3, -5), B(5,2) and C(-9,-3).

Find the angles of /_\ABC whose vertices are A(-1,3,2), B(2,3,5) and C(3,5,-2) .