(x-1)/(2x+1)+(2x+1)/(x-1)=2,x!=(-1)/(2),1

Solve by factorization: (x-1)/(2x+1)+(2x+1)/(x-1)=5/2,\ \ x!=-1/2,\ 1

Solve for x:(x-1)/(2x+1)+(2x+1)/(x-1)=2, where x!=-(1)/(2),1

Solve by factorization: (x-1)/(2x+1)+(2x+1)/(x-1)=(5)/(2),quad x!=-(1)/(2),1

(x-1) / (2x + 1) + (2x + 1) / (x-1) = (5) / (2), x! =-(1) / (2), 1

Solve for x : (x - 1)/(2x + 1) + (2x + 1)/(x -1) = 2 , where x ne - (1)/(2) , 1

Solve for x: (x-1)/(2x+1) +(2x+1)/(x-1)=2," where "x ne -(1)/(2),1

If f(x)=|{:(1,x,x+1),(2x,x(x-1),(x+1)x),(3x(x-1),x(x-1)(x-2),(x+1)x(x-1)):}| then

Express the following in the lowest terms. ((2x^(2)+1)/(x-1)+(x-1)/(x+1))xx((x^(2)-1)/(2x)):

Let x_(1) , x_(2) , x_(3) be the solution of tan^(-1) ((2x + 1)/(x +1 )) + tan ^(-1) ((2x - 1)/( x -1 )) = 2 tan ^(-1) ( x + 1) " where x_1 2x_(1) + x_(2) + x_(3)^(2) is equal to

Using the properties of determinants, prove that following : |{:(1,x,x+1),(2x,x(x-1),x(x+1)),(3x(1-x),x(x-1)(x-2),x(x+1)(x-1)):}|=6x^(2)(1-x^(2))