[7(y+3)-2(x+2)=14],[y(y-2)+3(x-3)=2]

Solve the following system of equations: 7(y+3)-2(x+2)=14,quad 4(y-2)+3(x-3)=2

7 (y + 3) -2 (x + 2) = 14.4 (y-2) +3 (x-3) = 2

Solve the following system of equations: 7(y+3)-2(x+2)=14 ,\ \ \ \ \ 4(y-2)+3(x-3)=2

Factorise (2x+3y)^(2)+14(2x+3y)(3x-y)-32(3x-y)^(2) .

Factorise (2x+3y)^(2)+14(2x+3y)(3x-y)-32(3x-y)^(2) .

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Solve for x and y if [(x^(2)),(y^(2))]+2[(2x), (3y)]=3[(7),(-3)]

Simplify: (3x+2y)(4x+3y)-(2x-y)(7x-3y)

{:(3x + 2y = 4),(2x - 3y = 7):}