A simple pendulum has a bob of mass m = 40 gm and a positive charge `q =4 xx 10^(-6) C`. It makes 20 oscillation in 4.5 s. A vertical upward electric field of magnitude `E = 2.5 xx 10^(4) N//C` is switched on in space. How much time will the simple pendulum will now take to complete 20 oscillation.

The bob of a simple pendulum has a mass of 40 g and a positive charge of 4.0 xx 10 ^(-5) C . It makes 20 oscillations in 45 s. A vertical electric field pointing upward and of magnitude 2.5 xx 10^ 4 NC^(-1) is switched on. How much time will it now take to complete 20 oscillations?

The bob of a simple pendulum has a mass of 60 g and a positive charge of 6xx10^(-6) C . It makes 30 oscillations in 50 s above earth's surface. A vertical electric field pointing upward and of magnitude 5xx10^(4) N//C is switched on. How much time will it now take to complete 60 oscillations ? (g=10 m//s^(2))

The bob of a simple pendulum is oscillating with a frequency of 25 Hz. How much time will the pendulum take to make 100 oscillations?

A bob of a simple pendulum of mass 40gm with a positive charge 4xx10^(-6)C is oscillating with a time period T_(1) .An electric field of intensity 3.6xx10^(4)N//C is applied vertically upwards.Now the time period is T_(2) the value of (T_(2))/(T_(1)) is (g=10//s^(2))

A pendulum bob of mass 80mg and carrying a charge of 2xx 10^(-8)C is at rest in a uniform, horizontal electric field of 20k Vm^-1. Find the tension in the thread.

A simple pendulum makes 10 oscillations in 20 seconds. What is the time period and frequency of its oscillation?

A pendulum bob of mass m = 80 mg, carrying a charge of q=2xx10^(-8)C , is at rest in a horizontal, uniform electric field of E = 20,000 V/m. The tension T in the thread of the pendulum and the angle alpha it makes with vertical, is (take g=9.8m//s^(2) )

A simple pendulum with a bob of mass m = 1 kg, charge q = 5muC and string length imis given a horizontal velocity a in a uniform electric field E = 2 xx 10^6 V/m at its bottommost point A, as shown in figure. It is given that the speed a is such that the particle leaves the circle at point C. Find the speed a (Take g = 10 m/ s^2 )

A pendulum bob of mass 30.7 xx 10^(-6)kg and carrying a chargee 2 xx 10^(-8)C is at rest in a horizontal uniform electric field of 20000V//m . The tension in the thread of the pendulum is (g = 9.8 m//s^(2))