Show that, for a given dipole, V & E cannot have the same magnitude at distance less than 2m from the dipole. Suppose that the distance is `sqrt(5)m`, determine the directions along which V & E are equal in magnitude.

Potential due to magnetic dipole at distance from centre of the dipole on axis of dipole is V.What will be potential at distance 2r from centre on the axis of dipole?

A short electric dipole has dipole moment p. Find the distance of farthest point from the dipole where (a) potential due to the dipole is V_0 (b) Electric field due to the dipole is E_0

A short electric dipole is situated at the origin of coordinate axis with its axis along x-axis and equator along y-axis. It is found that the magnitudes of the electric intensity and electric potential due to the dipole are equal at a point distance r=sqrt(5) m from origin. Find the position vector of the point in first quadrant.

For a given dipole at a poit (away from the center of dipole) intensity of the electric field is E. Charges of the dipole are brought closer such that distance between point charges is half, and magnitude of charges are also halved. The intensity of the field now at the same point becomes

If the force exerted by an electric dipole on a charge q at distance of 1 m is F, the force at a point 2 m away in the same direction will be

Consider a magnetic dipole kept in the north to south direction. Let P_1, P_2, Q_1, Q_3 be four points at the same distance from the dipole towareds north, south, east and west of the dipole respectively. The directions of the magnetic field due to the dipole are the same at

Calculate the magnitude of the force, due to an electric dipole of dipole moment 3.6xx10^(-29) C-m , on an electric 25mm from the center of the dipole , along the dipole axis. Assume that this distance is large relative to the dipole's charge separation.