An electron is released with a velocity of `5xx10^(6)ms^(-1)` in an electric field of `10^(3)NC^(-1)` which has been applied so as to oppose its motion. What distance would the electron travel and how much time could it take before it is brought to rest?

An electron moving with a speed of 5xx10^(6)m//s is shot parallel to the electric field of strength 1xx10^(3) N/C arranged so as to retard its motion. How far will the electron travel in the field before coming (momentarily) to rest? ( m_(e)=9.1xx10^(-31)kg )

An electron is moving with a velocity of 5 xx 10^(7) m/s in a magnetic field of 6 xx 10^(-4) T perpendicular to it. What is the frequency? Also find the energy of electron in MeV.

An electron moving with a velocity 5 xx 10^(6)ms^(-1)hati in the uniform electric field of 5 xx 10^(7)Vm^(-1)hatj Find the magnitude and direction of a minimum uniform magnetic field in tesla that will cause the electron to move undeviated along its original path .

An electron with a speed of 2.60 xx 10^(8) cm//s enters and electric field of magnitude 1.00 xx 10^(3)N//C , travelling along a field in the direction that retards its motion. (a) How far will the electron travel in the field before stopping momentarily, and (b) how much time will have elapsed ? (c ) If the region containing the electric field is 8.00 mm long (too short for the electroc to stop within it),what fraction of the electrons initial energy will be lost in that region ?

An electron with a speed 5.00xx10^6 m/s enters an electric field of magnitude 10^3 N/C, travelling along the field lies in the direction that retards its motion. a. How far will the electron travel in the field before stopping momentarily? b. How much time will have elapsed? c. If the regin with the electric field is only 8.00 mm long (too short from the electronn to stop with in it), what fraction of the elctron's initial kinetic energy wil be lost in that region.

An electron moving with a velocity of 5 xx 10^(4)ms^(-1) enters into a uniform electirc field and acquires a uniform acceleration of 10^(4)ms^(-2) in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time ?

An electron entering field normally with a velocity 4 xx 10^7 ms^(-1) travels a distance of 0.10 m in an electric field of intensity 3200 Vm^(-1) . What is the deviation from its path?

Two electrons each moving with a velocity of 10^(6) ms^(-1) are released towards eachother. What will be the closest distance of approach between them ?

An electron is projected with an initial velocity of 10^(7)ms^(-1) into an electric field between two parallel plates 1 cm apart. The electron enters the field at a point midway between the plates. If the electron just misses the positivity charged plate as it emerges from the field, find the magnnitude of the electric density between the plates. (Length of each plate is 2 cm, mass of electron= 9xx10^(-31) kg and charge of electron =1.6xx10^(-19) C)

An electron travelling with a speed of 5xx10^(3) ms^(-1) passes through an electric field with an acceleration of 10^(12)ms^(-2) . (i) How long will it take for the electron to double its speed ?(ii) What will be the distance covered by the electron in this time?