The region between two concentric spheres of radii 'a' and 'b', respectively (see figure), have volume charge density `rho=A/r`, where A is a constant and r is the distance from the centre. At the centre of the spheres is a point charge Q. The value of A such that the electric field in the region between the spheres will be constant, is:

A solid sphere of radius R has a volume charge density rho=rho_(0) r^(2) (where rho_(0) is a constant ans r is the distance from centre). At a distance x from its centre (for x lt R ), the electric field is directly proportional to :

A solid sphere of radius R has a charge Q distributed in its volume with a charge density rho=kr^a , where k and a are constants and r is the distance from its centre. If the electric field at r=(R)/(2) is 1/8 times that r=R , find the value of a.

A solid sphere of radius R is charged with volume charge density p=Kr^(n) , where K and n are constants and r is the distance from its centre. If electric field inside the sphere at distance r is proportional to r^(4) ,then find the value of n.

A solid sphere of radius R has a mass distributed in its volume of mass density rho=rho_(0) r, where rho_(0) is constant and r is distance from centre. Then moment of inertia about its diameter is

An insulating solid sphere of the radius R is charged in a non - uniform manner such that the volume charge density rho=(A)/(r ) , where A is a positive constant and r is the distance from the centre. The potential difference between the centre and surface of the sphere is

A solid non conducting sphere of radius R has a non-uniform charge distribution of volume charge density, rho=rho_(0)r/R , where rho_(0) is a constant and r is the distance from the centre of the sphere. Show that : (i) the total charge on the sphere is Q=pirho_(0)R^(3) (ii) the electric field inside the sphere has a magnitude given by, E=(KQr^(2))/R^(4)