A cube has sides of length L=0.2 m It is placed with one corner at the origin as shown in figure The electric field in uniform and given by `vec(E)=(2.5hat(i)-4.2hat(j))N//C` .Find the electric flux through the entire cube.

A cube has sides of length L = 0.2 m. It is placed with one corner at the origin as shown in figure. The electric field is uniform and given by E= (2.5 N//C) hati - (4.2 N//C) hatj . Find the electric flux through the entire cube.

A cube has sides of length L. It is placed with one corner atAthe origin as shown in figure. The electric field is uniform and given by E = - B hati + Chatj - Dhatk , where B, C and D are positive constants. (a) Find the electric flux through each of the six cube faces S_1, S_2, S_3 , S_4 and S_5 and S_6 . (b) Find the electric flux through the entire cube.

A cube has sides of length L . It is placed with one corner at the origin ( refer to Fig.2.119). The electric field is uniform and given by vec€ = - B hat (i) + C hat (j) - D hat(k) , where B , C , and D are positive constants. The total flux passing through the cube is

A cube has sides of length L = 0.300 m . It is placed with one corner at the origin ( refer to Fig.2.119).The electric field is not uniform but is given by vec( E) = ( -5.00 NC^(-1)) x hat(i) + (3.00 NC^(-1)) z hat(k) . The surface that have zero flux are

A cube has sides of length L = 0.300 m . It is placed with one corner at the origin ( refer to Fig.2.119).The electric field is not uniform but is given by vec( E) = ( -5.00 NC^(-1)) x hat(i) + (3.00 NC^(-1)) z hat(k) . The total flux passing through the cube is

A cube has sides of length L = 0.300 m . It is placed with one corner at the origin ( refer to Fig.2.119).The electric field is not uniform but is given by vec( E) = ( -5.00 NC^(-1)) x hat(i) + (3.00 NC^(-1)) z hat(k) . The total electric charge inside the cube is

A cube has sides of length L = 0.300 m . It is placed with one corner at the origin ( refer to Fig.2.119).The electric field is not uniform but is given by vec( E) = ( -5.00 NC^(-1)) x hat(i) + (3.00 NC^(-1)) z hat(k) . The flux passing through the surface S_(5) will be

If the electric field is given by 3 hat(i) + 2 hat(j) + 6 hat(k) . Find the electric flux through a surface area 20 unit lying in xy plane