Home
Class 12
PHYSICS
A continuous line of charge oflength 3d ...

A continuous line of charge oflength 3d lies along the x-axis, extending from `x + d` to` x + 4d` . the line carries a uniform linear charge density `lambda`.

In terms of d,`lambda` and any necessary physical constants, find the magnitude of the electric field at the origin:

A

`lambda//5piin_(0)d`

B

`lambda//4piin_(0)d`

C

`3lambda//16piin_(0)d`

D

`3lambda//8piin_(0)d`

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROSTATICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Numerical MCQs Single options Correct|64 Videos

  • ELECTROSTATICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Advance MCQs|40 Videos

  • ELECTROSTATICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Discussion Question|25 Videos

  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENT

    PHYSICS GALAXY - ASHISH ARORA|Exercise Advance MCQs|33 Videos

  • GEOMETRICAL OPTICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Problems|107 Videos

Similar Questions

Explore conceptually related problems

A continuous line of charge of length 3d lies along the x-axis, extending from x + d to x + 4d, The line carries a uniform linear charge density lambd . In terms of d, lambda and any necessary physical constant find the magnitude of the electric field at the origin.

Find the electric field at the origin due to the line charge (ABCD) of linear charge density lambda ,

Knowledge Check

  • Two parallel infinite line charges with linear charge densities +lambda C//m and -lambda C/m are placed at a distance of 2R in free space. What is the electric field mid-way between the two line charges?

    A
    `(lambda)/(2pi epsilon_(0) R)N//C`
    B
    zero
    C
    `(2lambda)/(pi epsilon_(0)R)N//C`
    D
    `(lambda)/(pi epsilon_(0)R)N//C`

  • A rod lies along the x-axis with one end at the origin and the other at x rarr oo . It carries a uniform charge lambda C/m. The electric field at the point x = -a on the axis will be

    A
    `vec(E) = (lambda)/(4pi epsilon_(0)a)(-hat(i))`
    B
    `vec(E) = (lambda)/(4pi epsilon_(0)a)(hat(i))`
    C
    `vec(E) = (lambda)/(2pi epsilon_(0)a)(-hat(i))`
    D
    `E = (lambda)/(2pi epsilon_(0)a)(hat(i))`

  • A rod lies along the X-axis with one end at the origin and the other at x rarr oo . It carries a uniform charge lambda Cm^(-1) . The electric field at the point x=-a on the axis will be

    A
    `E=lambda/(4pi epsi_(0)a) (-hat(i))`
    B
    `E=lambda/(4pi epsi_(0)a) (hat(i))`
    C
    `E=lambda/(2pi epsi_(0)a) (-hat(i))`
    D
    `E=lambda/(2pi epsi_(0)a) (hat(i))`

    • Similar Questions

    Explore conceptually related problems

    A rod of length L lies along the x-axis with its left end at the origin. It has a non-uniform charge density lamda=alphax , where a is a positive constant. (a) What are the units of alpha ? (b) Calculate the electric potential at point A where x = - d .

    Obtain the formula for the electric field due to a along thin wire of uniform linear charge density lambda without using Gauss's law.

    A rod of length L is placed along the x-axis between x=0 and x=L. The linear mass density is lambda such that lambda=a+bx . Find the mass of the rod.

    A rod of length L is placed along the x-axis between x = 0 and x = L. The linear density (mass/ length) lambda of the rod varies with the distance x from the origin as lambda = Rx . Here, R is a positive constant. Find the position of centre of mass of this rod.

    Obtain the formula for the electric field due to a long thin wire of uniform linear charge density lambda without using Gauss's law. [Hint. use Coulomb's law directly and evaluate the necessary integral].

    Home
    Profile