A hollow charged conductor has a tiny hole cut into its surface. Show that the electric field in the holes is `(sigma//2 in_(0)` `hat(n)`, where `hat(n)` is the unit vector in the outward normal direction, and `sigma` is the surface charge density near ther hole.

A hollow charged conductor has a tiny hole cut into its surface. Show that the electric field in the hole is ((sigma)/( 2 in_(0)))n , where hat(n) is the unit vector in the outward normal direction and sigma is the surface charge density near the hole .

The electric intensity at a point near a charged conductor of surface charge density sigma is

Show that the electric field at the surface of a charged conductor is given by vecE = (sigma)/(epsi_(0)) hatn , where sigma is the surface charge density and hatn is a unit vector normal to the surface in the outward direction .

A spherical charged conductor has sigma as the surface density of charge. The electric field on its surface is E. If the radius of the sphere is doubled keeping the surface density of charge unchanged, what will be the electric field on the surface of the new sphere -

The surface charge density of a thin charged disc of radius R is sigma . The value of the electric field at the centre of the disc is (sigma)/(2in_(o)) . With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc reduces by