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Electrically charged drops of mercury fall from an altitude h into a spherical metal vessel of radius R. There is a small opening in the upper part of the vessel. The mass of each drop is m, and the charge on the drop is Q. What will be the number n of the last drop that can still enter the sphere?

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The correct Answer is:
`[ n = (4 pi in_(0)"mg"(h-R)R)/(Q^(2))]`
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