An X-ray tube operates at `20k V`. Find the maximum speed of the electron strinking the anode , given the charge of electron is `1.6 xx 10^(-19)` coulomb and mass of electron is `9 xx 10^(-31) kg`.

An X- ray tube operates at 27 kV . Find the maximum speed of an electron striking the anticathode. Given mass of electron =9xx10^(31)kg and charge on electron =1.6xx10^(-19)C .

The rest mass of an electron is 9.11xx10^(-31) kg. Molar mass of the electron is

The charge on the electron is 1.6 xx 10^(-19) C . The order of magnitude is

If mass of an electron is 9.1xx10^(-31) kg, the number of electrons in 1 mg is

The Velocity of electrons accelerated bt potential difference of 1xx10^(4) V (the charge of the electron is 1.6xx10^(-19) C and mass is 9.11xx10^(-31) kg) is

What is the number of electrons that would weight 1 kg? Mass of an electron is 9.11 xx 10^-31 kg .

An electron is accelerated under a potential difference of 182 V. the maximum velocity of electron will be (Given, charge of an electron is 1.6xx10^(-19)C ms^(-1) and its mass is 9.1xx10^(-31)kg )

An electron travels in a circular path of radius 20cm in a magnetic field 2xx10^-3T (i) Calculate the speed of the electron (ii) What is the potential difference through which the electron must be accelerated to acquire this speed? Charge of electron =1*6xx10^(-19)C . Mass of electron =9xx10^(-31)kg .