(sec theta-cos theta)(cot theta+tan theta)=tan theta sec theta

Prove :(sec theta-cos theta)(cot theta+tan theta)=tan .sec theta

prove that (sec theta-tan theta-1)/(sec theta+tan theta-1)=tan theta-sec theta

Prove: (cos ec theta-sec theta)(cot theta-tan theta)=(cos ec theta+sec theta)(sec theta cos ec theta-2)

Prove the following identity : (sec theta-cos theta) (cosec theta-sin theta)=1/(tan theta+ cot theta) .

(cos ec theta-sin theta)(sec theta-cos theta)(tan theta+cot theta)=1

Find ("cosec" theta-sin theta)(sec theta-cos theta)(tan theta+cot theta) :?

If cot theta-tan theta=sec theta then theta=

Prove that : (sec theta-tan theta)/(sec theta+tan theta)= 1-2 sec theta tan theta+ 2 tan^2 theta .

Simplify sectheta[(sec theta,tan theta),(tan theta,sec theta)]-tan theta[(tan theta, sec theta),(sec theta, tan theta)]

prove that: (tan theta)/(1-cot theta)+(cot theta)/(1-tan theta)=1+sec theta cosec theta