One mole of an ideal gas is warmed slowly so that it goes form the `PV` state (`P_(f) V_(i)`) to `(3P_(i), 3V_(i)`) in such a way that the pressure of the gas is directly proportional to the volume. (a) How much work is done on the as in the process? (b) How is the temperature of the gas related to its volume during this process?
Text Solution
Verified by Experts
The correct Answer is:
`(a) -4P_(i)V_(i) (b) T = ((P_(i))/(nRV_(i)))V^(2)`
In a process the pressure of a gas is inversely proportional to the square of the volume. If temperature of the gas increases, then work done by the gas:
An ideal gas goes from the state i to the state int as shown in .the work done by the gas during the process
In a process, the pressure of an ideal gas is proportional to square of the volume of the gas. If the temperature of the gas increases in this process, then work done by this gas
A gas expands under constant pressure P from volume V_(1) to V_(2) The work done by the gas is
The variation of pressure P with volume V for an ideal diatomic gas is parabolic as shown in the figure. The molar specific heat of the gas during this process is
In figure, P-V curve of an ideal gas is given. During the process, the cumulative work done by the gas