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A particles starts from point x=-sqrt(3)...

A particles starts from point `x=-sqrt(3)/(2) A` and move towards negative extrene as shown . If the time period of oscillation is T , them

A

The equation of the SHM is `x= A sin ((2pi)/(T)+(4pi)/(3))`

B

The time taken by the particle tto go directly from its initial position to negative extreme is `(T)/(12)`

C

The time taken by the particle to reach at mean position is `(T)/(3)`

D

The equation of the SHM is ` x= A sin ((2pi)/(T)+(pi)/(3))`

Text Solution

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A, B, C
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