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The bob of a simple pendulum is displace...

The bob of a simple pendulum is displaced from its equilibrium position 'O' to a position 'Q' which is at a height 'h' above 'O' and the bob is then released. Assuming the mass of the bob to be 'm' and time period of oscillation to be `2.0s`, the tension in the string when the bob passes through 'O' is

A

`m(g+pisqrt(2gh))`

B

`m(g+sqrt(pi^(2)gh))`

C

`m(g+sqrt((pi^(2))/2)gh)`

D

`m(g+sqrt((pi^(2))/3)gh)`

Text Solution

Verified by Experts

The correct Answer is:
A
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