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The increase in internal energy of 1 kg ...

The increase in internal energy of 1 kg of water at `100^(@)` C when it is converted into steam at the same temperature and 1 atm (100 kPa) will be :
[The density of water and steam are `1000 kg//m^(3) "and" 0.6 kg//m^(3)` respectively. The latent heat of vapourisation of water is `2.25xx10^(6) J//kg`.]

A

`2.08xx10^(6) J`

B

`4xx10^(7) J`

C

`3.27xx10^(8) J`

D

`5xx10^(9) J`

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The correct Answer is:
A
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calculate the increase in internal energy of 1 kg of water at 100(0)C when it is converted into steam at the same temperature and at 1atm (100 kPa). The density of water and steam are 1000 kg m^(-3) and 0.6 kg m^(-3) respectively. The latent heat of vaporization of water =2.25xx10^(6) J kg^(1) .

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5.00 kg of liquid water is heated to 100. 0^@ C in a closed system At this temperature , the density of liquid water is 958 kg/ m^3 . The pressure is maintained at atmospheric pressure of 1.01 xx 10^5 Pa. A moveable piston of negligible weight rests on the surface of the water. The water is then converted to steam by adding an additional amount of heat to the system. When all of the water is converted, the final volume of the steam is 8.50 m^3 . The latent heat of vaporization of water is 2.26 xx 10^6 J/kg. What is the change in the internal energy during this isothermal process?

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