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The pressure-volume work for an ideal ga...

The pressure-volume work for an ideal gas can be calculated by using the expression `omega=-underset(upsilon_(1))int overset(upsilon_(1))P_(ex)dV.` The work can also be calculated form the Pv, plot by using the area under the curve within the specified limits. When an ideal gas is compressed (a) reversiblity or (b) irrevesibly form volume `V_(i) "to"V_(f)` choose the correct option:

A

`omega("reversible")=omega("irreversible")`

B

`omega("reversible")ltomega("irreversible")`

C

`omega("reversible")gtomega("irrversible")`

D

`omega("reversible")=omega("irrversible")`

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The correct Answer is:
B
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The pressure volume work for an ideal gas can be calculated by using the expression w=-int_(V_(i))^(v_(f))Pex dV . The work can also be calculated from the pV-plot by using the area under the curve within the specified limits. When an ideal gas is compressed (a) reversibly or (B) irreversibly from volume V_(i) to V_(f) choose the correct option.

For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using expression = -nRT ln.(V_(f))/(V_(i)) . A sample containing 1.0 mol of an ideal gas is expanded isothermally and reversible to ten times of its original volume, in two separate experiments. The expansion is carried out at 300 K and at 600 K respectively. Choose the correct option

A gaseous sample is generally allowed to do only expansion // compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion // compression the states of gases are not defined). The work done can be calculated using dw= -P_(ext)dV while in case of reversible process the work done can be calculated using dw= -PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since P=(nRT)/(V) , so w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i))) Since dw= PdV so magnitude of work done can also be calculated by calculating the area under the PV curve of the reversible process in PV diagram. If four identical samples of an ideal gas initially at similar state (P_(0),V_(0),T_(0)) are allowed to expand to double their volumes by four different process. I: by isothermal irreversible process II: by reversible process having equation P^(2)V= constant III. by reversible adiabatic process IV. by irreversible adiabatic expansion against constant external pressure. Then, in the graph shown in the final state is represented by four different points then, the correct match can be

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