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2(Ag)toB(g), deltaH=-20kcal//mol. In a c...

`2(Ag)toB(g), deltaH=-20kcal//mol`. In a closed rigid container, 0.2mole of `A(g)` at constant temperature `727^(@)C` convert into B(g) then, change in heat energy in the process will be:
`(R=2cal//"mole"-K)`

A

`-12kcal`

B

`-1.8kacl`

C

`-2.4kcal`

D

`0.24kcal`

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The correct Answer is:
B
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