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The average Xe-F bond energy is 34Kcal//...

The average `Xe-F` bond energy is `34Kcal//mol` , first `I.E`. Of `Xe` is `279Kcal//mol` , electron affinity of `F` is `85Kcal//mol` . Then, the enthalpy change for the reaction
`XeF_(4)rarrXe^(+)+F^(-)+F_(2)+F` will be

A

367 kcal`//`mole

B

425 kcal`//`mole

C

292 kcal`//`mole

D

392 kcal`//`mole

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The correct Answer is:
C
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