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The stande enthalpy of formation for NH(...

The stande enthalpy of formation for `NH_(3)(g)`is `-46.1KJxxmol^(-1)` .Calculate `DeltaH^(@)` for the reaction :
`2NH_(3)(g)toN_(2)(g)+3H_(2)(g)`

A

`-92.2KJ`

B

`-46.1KJ`

C

`46.1Kj`

D

`92.2KJ`

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The correct Answer is:
d
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