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12.5 millinmole of NH(4)NO(3) dissolved ...

12.5 millinmole of `NH_(4)NO_(3)` dissolved in enough water to make 25.0 mL of solution. The initial temperature is `25.8^(@)C` and temperature after solid dissolves is `21.8^(@)C`. Calculate the enthalpy of solution for the `NH_(4)NO_(3)(s) "in kcal"//"mole"`.
[Given : Density of the solution `=1 "gm"//"ml"` and heat capacity of solution `(1cal)/(gm-K)`]

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