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Consider a number N=21P53Q4 No of orded...

Consider a number `N=21P53Q4` No of ordeder pairs `(p,Q)` s that the as 'N' is tivisible by a is

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`N = 21P53Q4`
For this number to be divisible by `9`, sum of all the digits should be divisible by `9`.
Sum of all the digits of `N = 2+1+P+5+3+Q+4 = 15+P+Q`
So, this number to be divisible by `9`,
`P+Q = 3 or P+Q = 12`
When `P+Q = 3`,then the ordered pairs will be,
`(0,3),(1,2),(2,1),(3,0)`.
So, total ordered pair in this case is `4`.
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