Seven years ago Varun’s age was five times the square of Swati’s age. Three years hence Swati’s age will be two fifth of Varun’s age. Find their present ages.

Seven year ago, Varun's age was five times the square of swati's age. Three years hence Swati's age will be two fifth of Varun's age. Find their present ages.

Seven years ago Varuns age was five xx the square of Swatis age.Three years hence Swatis age will be two fifth of Varuns age.Find their present ages.

The sum of two numbers is 15. If the sum of their reciprocals is 3/10 . Find the numbers. Or Seven years ago keshav's age was five times the square of Raghav's age. Three years hence Raghav's age will be two fifth of Keshav's age. Find their present ages.

7 years ago Alka's age was 5 times the square of Swati's age. Three years hence Swati's age will be 2/5 th of Alka's age. Find their present ages.

The present age of Varun is 10 more than square of Swati's age. Five years hence Swati's age will be one-fourth of Varun's age. Find their present ages.

Two years ago, a man's age was three times the square of his son's age. In three years time, his age will be four times his son's age. Find their present ages.

Five years ago, A's age was four times the age of B. Five years hence , A's age will be twice the age of B. Find their present ages.

The present age of a father is three years more than three times the age of the son. Three years hence father’s age will be 10 years more than twice the age of the son. Determine their present ages.

The present age of a father is three years more than three times the age of the son. Three years hence father’s age will be 10 years more than twice the age of the son. Determine their present ages.

After 15 years, Hema’s age will become four times that of her present age. Find her present Age.