The excess (equal to number) number of electrons that must be placed on each of two small spheres spaced `3cm` apart with force of repulsion between the spheres of br `10^(-19)N` is

Calculate the excess number of electrons that must be placed on each of the two similar uncharged spheres that are located 5 cm part of (in air), such that the force of repulsion between them is 36 xx 10^(-19) N .

How far two electrons should be placed so that the force of repulsion between them is equal to the weight of an electron ?

Two charges of 1.0 C each are placed one meter apart in free space.The force between them will be.

A small uncharged sphere is placed in contact with an equal and similar charged sphere and then removed to a distance of 4 cm. The force of repulsion between them is now 9xx10^(-5) N. What was the original charges in the charged sphere?

Two spheres, each of mass 625 kg, are placed with their centres 50 cm apart. The gravitational force between them is

Two spheres, each of mass 625 kg, are placed with their centres 50 cm apart. The gravitational force between them is

Two identical metallic spheres, having unequal opposite charges are placed at a distance of 0.50 m apart in air. After bringing them in ir contact with each other, they are placed at the same distance apart. Now, the force of repulsion between them is 0.108 N. Calculate the final charge on each of them.

What is the force between two small charged of 2 xx 10^(-7) C placed 30 cm apart in air?

What is the force between two small charged of 2 xx 10^(-7) C placed 30 cm apart in air?