`int_0^1000 e^(x-[x])dx`

int_0^(100)e^(x-[x])dx=

Integrate the following int_0^50e^(x-[x])dx

int_0^a e^(x-[x])dx=10e-9 then find a

The value of sum_(n=1)^1000 int_(n-1)^n e^(x-[x])dx , where [x] is the greatest integer function, is (A) (e^1000-1)/1000 (B) (e-1)/1000 (C) (e^1000-1)/(e-1) (D) 1000(e-1)

The value of sum_(n=1)^1000 int_(n-1)^n e^(x-[x])dx , where [x] is the greatest integer function, is (A) (e^1000-1)/1000 (B) (e-1)/1000 (C) (e^1000-1)/(e-1) (D) 1000(e-1)

int_0^1 e^x dx

int_0^1 e^-x/(1+e^x)dx

int_0^10 [x]e^([x])/e^(x-1)dx where [x] is GIF

Evaluate int_0^(1)e^(x)dx