Let `D(x_4,y_4) ` be a point such that `ABCD` is a square and `M` and `P` are the midpoints of the sides `BC & CD` respectively, then

Let ABCD be a parallelogram. Let X and Y be the midpoints of the sides BC and AD respectively. Let M and N be the midpoints of the sides AB and CD respectively. Consider the following statements : 1. The straight line MX cannot be parallel to YN. 2. The straight lines AC, BD, XY and MN meet at a point. Which of the above statements is/are correct?

ABCD is a parallelogram . If P and Q are the mid-points of [BC] and [CD] respectively, show that vec AP + vec AQ=

P is any point on the side BC of a triangle ABC . P is joined to a. If D and E are the midpoints of the sides AB and AC respectively and M and N are the midpoints of BP and CP respectively then quadrilateral DENM is

ABCD is a quadrilateral,AB and CD are parallel, P and Q are the midpoints of the sides BC and AD respectively. They, the value of bar(AB)+bar(DC) is -

Let ABCD be a rectangle. Let P, Q, R, S be the mid-points of sides AB, BC, CD, DA respectively. Then the quadrilateral PQRS is a

If M and N are the mid - points of the sides BC and CD respectively of a parallelogram ABCD, then AM + AN equals

ABCD is a rectangle and P,Q,R and S are the mid points of the sides AB,BC,CD and DA respectively. Show that the quadrilateral PQRS is a rhombus.

ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus.