`tan7 0^(@)-tan2 0^(@)=kcot4 0^(@)=>k=`

If cot 20^@=p then (tan16 0^(@)-tan11 0^(@))/(1+tan16 0^(@)tan11 0^(@))=

(2tan3 0^(@))/(1-tan^2 3 0^(@))

(2tan3 0^(@))/(1-tan^2 3 0^(@))

The value of (tan7 0^0-tan2 0^0)/(tan5 0^0)=

The general solution of the equation tan(x+20^@)tan(x-4 0^(@))=tan(x-2 0^(@))tan(x+4 0^(@)) is

The value of (tan70^(0)-tan20^(0))/(tan50^(0)) =

Prove that tan9^(0)-tan27^(0)-cot27^(0)+cot9^(0)=4

Evaluate :tan7^(0)tan23^(@)tan60^(@)tan67^(0)tan83^(@)

tan9^(0)-tan27^(0)-tan63^(@)+tan81^(@)

Evaluate: (sec theta csc(90^(0)-theta)-tan theta cot(90^(0)-theta)+sin^(2)55^(0)+sin^(2)35^(@))/(tan10^(0)tan20^(0)tan60^(@)tan70^(0)tan80^(0))