A homogenous rod of length l=etax and ma...

A homogenous rod of length `l=etax` and mass `M` is lying on a smooth horizontal floor. A bullet of mass `m` hits the rod at a distance `x` from the middle of the rod at a velocity `v_(0)` perpendicular to the rod and comes to rest after collision. If the velocity of the farther end of the rod just after the impact is in the opposite direction of `v_(0)` then:

`eta gt 3`

`eta lt 3`

`eta gt 6`

`eta lt 6`

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The correct Answer is:

A uniform rod of length l and mass 2m rests on a smooth horizontal table. A point of mass m moving horizontally at right angle to the rod with velocity v collides with one end of the rod and sticks to it, then:

angular velocity of the system after collision is `v/l`

angular velocity of the system after collision is `v/(2l)`

the loss in kinetic enerlgy of the system as a whole as a result of the collision is `(mv^(2))/6`

the loss in kinetic energy of the system as a whole as a result of the collision is `(7mv^(2))/24`

`(Mv)/(M+m)`

`(mv)/(M+m)`

`(2mv)/(M+m)`

`(2Mv)/(M+m)`

The point is a distance `(1//3) l` from the end where the mass strikes.

The point is a distance `(2//3) l` from the end where the mass strikes.

The point is a distance `(2//5) l` from the end where the mass strikes

The point is a distance` (1//5) l` from the end where the mass strikes