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A thin circular ring of mass M and radiu...

A thin circular ring of mass M and radius r is rotating about its ais with an angular speed `omega`. Two particles having mas m each are now attached at diametrically opposite points. The angular speed of the ring will become

A

`(omegaM)/(M+m)`

B

`(omegaM)/(M+2m)`

C

`(omega(M-2m))/(M+2m)`

D

`(omega(M+2m))/M`

Text Solution

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The correct Answer is:
B
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