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A spool of mass m has moment of inertia ...

A spool of mass `m` has moment of inertia `I= 2mR^(2)` about its axis of symmetry. The inner and outer radius of spool `R` and `2R` respectively. Thread is wounded on the inner cylinder and its one end is pulled a force F acting at angle `theta` with horizontal. The surface is sufficiently rough and th.e spool never slides on the surface.

For `theta=0^(@)`, the acceletation of spool is

A

`F/m`

B

`F/(2m)`

C

`F/(6m)`

D

`F/(3m)`

Text Solution

Verified by Experts

The correct Answer is:
D
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