`(1 + sin phi + i cos phi)/(1 + sin phi - i cos phi)^n = cos (n pi/2 - n phi) + i sin (n pi/2 - n phi)`

(3 cos phi+cos 3 phi)/(3 sin phi-sin 3 phi)=

If a sin phi+b cos phi=c then a cos phi-b sin phi is

Prove: (sin phi - cos phi) ^(2) =1 - sin 2 phi.

Find int( (3 sin phi-2) cosphi)/(5-cos ^2 phi-4 sin phi) d phi

int((3sin phi-2)cos phi)/(5-cos phi-4sin phi)d phi

int(2sin2 phi-cos phi)/(6-cos^(2)phi-4sin phi)d phi

Express the following in a + ib form: (a) ((cos alpha + i sin alpha)^(4))/((sin beta + i cos beta)^(5)) (b) ((1+ cos phi + i sin phi)/(1 + cos phi - isin phi))^(n) (c) ((cos alpha + i sin alpha)(cos beta + i sin beta))/((cos gamma + i sin gamma)(cos delta + i sin delta))

The value of ((sin theta + sin phi)/(cos theta + cos phi)+ (cos theta - cos phi)/(sin theta - sin phi)) is :