In the Fig. shown pulley moves with acceleration `vec(v)_(P)`. Let acceleration of blocks `m_(1)` and `m_(2)` w.r.t. ground are `vec(v)_(1)` and

In the fig, find the acceleration of m_(1) and m_(2) .

In the fig, find the acceleration of m_(1) and m_(2)

If the pulley is massles and moves with an upward acceleration a_(0) . Find the acceleration of (m_1)and (m_2) w.r.t to elevator.

In the figure shown, the acceleration of block of mass m_(2) is 2m//s^(2) . The acceleration of m_(1) :

When we ignore friction and mass of pulley what would be the accelerations of the two blocks m_(1) and m_(2) .

In the arrangement shown in fig., if the acceleration of B is vec(a) . Then find the acceleration of A.

In the pulley system shown here, find the relationship between acceleration of m_(1),m_(2) and m_(3)

If block A is moving with an acceleration of 5ms^(-2) , the acceleration of B w.r.t. ground is

In the figure acceleration of bodies A,B and C are shown with directions. Values b and c are w.r.t. ground. Whereas a is acceleration of block A w.r.t. wedge C. accelerationof block A w.r.t. ground is sqrt(beta) m//s^(2) . Find beta (use b=c= 1 m//s^(2), theta=60^(@) )

Five forces vec(F)_(1) ,vec(F)_(2) , vec(F)_(3) , vec(F)_(4) , and vec(F)_(5) , are acting on a particle of mass 2.0kg so that is moving with 4m//s^(2) in east direction. If vec(F)_(1) force is removed, then the acceleration becomes 7m//s^(2) in north, then the acceleration of the block if only vec(F)_(1) is action will be: