Home
Class 11
PHYSICS
In the Fig. shown a time dependent force...

In the Fig. shown a time dependent force F expressed as `F=kt` is applied on a block of mass 5 kg. Coefficient of static and kinetic friction is `mu_(s)=0.4` and `mu_(k)=0.3`. Motion begins when `t=2` sec draw a acceleration vs time graph for block. `(m=5 kg, mu_(s)=0.4, mu_(k)=0.3)`

Answer

Step by step text solution for In the Fig. shown a time dependent force F expressed as F=kt is applied on a block of mass 5 kg. Coefficient of static and kinetic friction is mu_(s)=0.4 and mu_(k)=0.3. Motion begins when t=2 sec draw a acceleration vs time graph for block. (m=5 kg, mu_(s)=0.4, mu_(k)=0.3) by PHYSICS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • FORCE ANALYSIS

    ANURAG MISHRA|Exercise level 1|103 Videos
  • FORCE ANALYSIS

    ANURAG MISHRA|Exercise Level-2|73 Videos
  • FORCE ANALYSIS

    ANURAG MISHRA|Exercise Matching type|13 Videos
  • DESCRIPTION OF MOTION

    ANURAG MISHRA|Exercise Level-3|34 Videos
  • IMPULSE AND MOMENTUM

    ANURAG MISHRA|Exercise matching|3 Videos

Similar Questions

Explore conceptually related problems

In the figure shown, if friction coefficient of block 1 kg and 2kg with inclined plane is mu_(1) = 0.5 and mu_(2) = 0.4 respectively, then

Coefficient of kinetic friction and coefficient of static friction between two blocks is mu_(k) and mu_(s) respectively. In general

Knowledge Check

  • A block of mass M is sliding down the plane. Coefficient of static friction is mu_(s) and kinetic friction is mu_(k) . Then friction force acting on the block is :

    A
    `(F+Mg)sin theta`
    B
    `mu_(k)(F+Mg)cos theta`
    C
    `mu_(s) Mg cos theta`
    D
    `(Mg+F)sin theta`
  • A force F=2t is spplied at t=0 sec to the block of mass m placed on a rough horizontal surface. The coefficient of static and kinetic friction between the block and surface are mu_S and mu_k rspectively. Which of the following graphs best represents the acceleration vs time of the block (mu_Sgtmu_k) ?

    A
    B
    C
    D
  • In Fig the block are at rest a force of 10 N act on the block of 4 kg mass .The coefficient of staic friction and the coefficient of kinetic friction are mu_(s) = 0.2 and mu_(s) = 0.15 for both the surface in contact The magnitudeof frcition force acting between the surface of contact between the 2 kg and 4 kg block in this situation is

    A
    `3 N`
    B
    `4 N`
    C
    `3.33 N`
    D
    Zero
  • Similar Questions

    Explore conceptually related problems

    A block of mass 5kg is resting on a rough surface as shown in the figure. It is acted upon by a force of F towards right. Find frictional force acting on block when F = 5N ( mu_(s) =0.6 , mu_(k) = 0.5)

    If the friction coefficient between the blocks are mu_(s) = 0.52 and mu_(k) = 0.50 , in how much time , the upper block will lose contact with the lower block.

    A block mass m = 2 kg is accelerating by a force F = 20 N applied on a smooth light pully as shown in fig 7.86 If the coefficient of kinetic friction between the block and the surface is mu = 0.3 find its acceleration

    A block of mass 5kg is lying on a rough horizontal surface. The coefficient of static and kinetic friction are 0.3 and 0.1 and 10m//s^(-2) . If a horizontal force of 50N is applied on the block, the frictional force is

    A block of mass m is placed over a rogh surface with coefficents of static and kinetic as mu_(s) and mu _(k) . A force F is applied to move block .Surface f is the force of fricty=tion between block and ound . Then chose the wrong opition (s).