`m=20 kg, mu_(s)=0.5`, find friction on block.

In the arrangement shown in figure pulley P can move whereas other two pulleys are fixed. All of them are light. String is light and inextensible. The coefficient of friction between 2 kg and 3 kg block is mu = 0.75 and that between 3 kg block and the table is mu = 0.5 . The system is released from rest (i) Find maximum value of mass M, so that the system does not move. Find friction force between 2 kg and 3 kg blocks in this case. (ii) If M = 4 kg, find the tension in the string attached to 2 kg block. (iii) If M = 4 kg and mu_(1) = 0.9 , find friction force between the two blocks, and acceleration of M. (iv) Find acceleration of M if m_(1) = 0.75, m_(2) = -0.9 and M = 4 kg.

A prismatic block of mass m is kept on a groove . The bottom line of the groove makes an angle theta with horizontal . The angle between is phi If the groove is symmetrical with the normal to the inclined plane containing the bottom line of the groove a. Find the coefficient of friction mu_(0) between the block and groove so that the block begins to slide. b. If mu gt mu_(0) find the friction force on the block. c. If mu lt mu_(0) find the acceleration of the block.

A block of mass m is kept on the floor of a freely falling lift .During the free fall of the lift, the block is pulled horizontally with a force of F = 5 N, mu_(s) = 0.1 The friction force on the block will be

The coefficient of friction between block A of mass m_(1)=5kg and block B of mass m_(2)=10 kg is mu_(2)=0.5 . There is no friction froce between block B and fixed horizontal surface. A force of 300N acts on block B in horizontal direction and a horizontal force of magnitude F acts on block A as shown , both towards right. Initially there is no relative motion between the blocks. The minimum value of F such that relative motion starts between A and B is :

A force of 200N is applied as shown in the figure on block of 3 kg. The coefficient of friction between the block and the wall is 0.3. Find the friction acting on the block. (in N) {Take g = 10 m//s^(2)

In the figure shown, if friction coefficient of block 1 kg and 2kg with inclined plane is mu_(1) = 0.5 and mu_(2) = 0.4 respectively, then

A block of mass M is sliding down the plane. Coefficient of static friction is mu_(s) and kinetic friction is mu_(k) . Then friction force acting on the block is :

A block of mass 5kg is resting on a rough surface as shown in the figure. It is acted upon by a force of F towards right. Find frictional force acting on block when F = 5N ( mu_(s) =0.6 , mu_(k) = 0.5)

A block of mass 5kg is resting on a rough surface as shown in the figure. It is acted upon by a force of F towards right. Find frictional force acting on block when 50N ( mu_(s) =0.6 , mu_(k) = 0.5) [ g = 10ms^(-2) ]

A block of mass m is kept on a horizontal table. If the static friction coefficient is mu ., find the frictional force acting on the block.