Coefficient of friction between 5 kg and 10 kg block is 0.5. If friction between them is 20 N. What is the value of force being applied on 5 kg. The floor is frictionless

Coefficient of friction between 5kg and 10 kg block is 0.5 and that between floor and 10 kg block is 0.8 if friction between floor and 10 kg block is 20 N what is the value of force (in N) being applied on 5 kg

A system of two blocks is shown in figure. Friction coefficient between 5 kg and 10 kg block is mu=0.6 and between 10 kg and ground is mu=0.4 What will be the maximum value of force F applied at the lower block so that 5 kg block does not slip w.r.t. 10 kg . (g=10m//sec^(2)). The force applied at the upper block is having fixed magnitude of 80 N (both forces start to act simultaneously)

A block A of mass 2 kg rests on another block B of mass 8 kg which rests on a horizontal floor. The coefficient of friction between A and B is 0.2 while that between B and floor is 0.5. when a horizontal force of 25 N is applied on the block B. the force of friction between A and B is

Block A of mass 2kg is placed over a block B of mass 8kg . The combination is placed on a rough horizontal surface. If g=10ms^(-2) , coefficient of friction between B and floor =0.5 , coefficient of friction between B and floor =0.5 , coefficient of friction between A and B=0.4 and a horizontal force of 10N is applied on 8kg block, then the force of friction between A and B is.

A block A of mass 2 kg rests on another block B of mass 8 kg which rests on a horizontal floor. The coefficient of friction between A and B is 0.2 while that between B and floor is 0.5 .When a horizontal floor F of 25 N is applied on the block B the force of friction between A and B is

Consider the shown arrangement. The coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and of 12 N is applied on the 2 kg block as shown in the figure, the acceleration of the 4 kg block would be

In the diagram shown coefficient of friction between 2 kg block and 4 kg block is mu =0.1 and between 4 kg and ground is mu =0.2 then answer the following quwstions .(tis time) Force of friction on 2 kg block at t=(1)/(2) s will be

The coefficient of friction between 4 kg and 5kg blocks is 0.2 and between 5kg block and grond is 0.1 respectively Choose the correct statements.

Consider the arrangement shown in the figure. The coefficient of friction between the two blocks is 0.5 and between the 4 kg block and the horizontal surface is 0.4. If a horizontal force of 12 N is applied on the 4 kg block, the acceleration of the 2 kg block would be