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a particle is moving in a circle of radi...

a particle is moving in a circle of radius R in such a way that at any instant the normal and the tangential component of its acceleration are equal. If its speed at `t=0` is `v_(0)` then time it takes to complete the first revolution is `R/(alphav_(0))(1-e^(-betapi))`. Find the value of `(alpha+beta)`.

A

`R//u_(0)`

B

`u_(0)//R`

C

`(R)/(u_(0))(1-e^(-2pi))`

D

`(R)/(u_(0)) e^(-2pi)`

Text Solution

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The correct Answer is:
c
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