A body moves on a horizontal circular road of radius of r, with a tangential acceleration `a_(T)`. Coefficient of friction between the body and road surface is `mu`. It begin to slip when it's speed is `v`, then :

Options

A. `v^(2)= mu rg`
B. `ug=(v^(2))/(r)+a_(T)`
C. `mu^(2)g^(2)=(v^(4))/(r^(2))+a_(T)^(2)`
D. The force of friction makes an angle `tan^(-1)((v^(2))/(a_(T)xxr))` with direction of motion at point of slipping.

Answer

b,c