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A very small cube of mass 2kg is placed ...

A very small cube of mass 2kg is placed on the surface of a funnel as shown in figure. The funnel is rotating about its vertical axis of symmetry with angular velocity `omega`. The wall of funnel makes an angle `37^(@)` with horizontal. The distance of cube from the axis of rotation is 20 cm and friction coefficient is `mu` (Take `g = 10 m//s^(2)`)

The friction force acting between the block and surface (if `mu = 0.3`) of funnel at `omega = 5 rad//s` is :

A

6.6 N

B

4 N

C

2.2 N

D

zero

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Verified by Experts

The correct Answer is:
b
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A very small cube of mass 2kg is placed on the surface of a funnel as shown in figure. The funnel is rotating about its vertical axis of symmetry with angular velocity omega . The wall of funnel makes an angle 37^(@) with horizontal. The distance of cube from the axis of rotation is 20 cm and friction coefficient is mu (Take g = 10 m//s^(2) ) The maximum value of angular velocity for which no relative slipping occur and also direction of frictional force is : (take mu = 2//3 )

A very small cube of mass 2kg is placed on the surface of a funnel as shown in figure. The funnel is rotating about its vertical axis of symmetry with angular velocity omega . The wall of funnel makes an angle 37^(@) with horizontal. The distance of cube from the axis of rotation is 20 cm and friction coefficient is mu (Take g = 10 m//s^(2) ) The mimimum value of angular velocity for which relative slipping occurs and also the direction of frictional force acting mu = 2//3 :

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