A `F^32` radio nuclide with half-life `T=14.3` days is produced in a reactor at a constant rate `q=2xx10^9` nuclei per second. How soon after the beginning of production of that radio nuclide will its activity be equal to `R=10^9` disintegration per second?

A radio nuclide with half life T= 14.3 daysis produced in a reactor at a constant rate q=10^(9) nuclei persecond. How soon after the beginning of production of that radio nuclide will, its activity be equal to A=10^(8) disintegrations per second. Plot a rough graph of its activity with time.

A .^(32)P radionuclide with half - life T = 14.3 days is produced in a reactor at a constant rate q=2.7xx10^(9) nuclei per second. How soon after the beginning of production of that nuclide will its activity be equal to A=1.0xx10^(9)dis.//s ?

A radionuclide with half - life 1620 s is produced in a reactor at a constant rate of 1000 nuclei per second. During each decay energy, 200 MeV is released. If the production of radionuclides started at t = 0, then the rate of release of energy at t = 3240 s is

A radionuclide with half life T is produced in a reactor at a constnat rate p nuclei per second. During each decay, energy E_(0) is released. If production of radionuclide is started at t=0, calculate (a) rate of release of energy as a function of time (b) total energy released upto time t

A radio nuclide with disintegration constant lambda is produced in a reactor at a constant rate alpha nuclei per second. During each decay energy E_0 is released. 20% of this energy is utilized in increasing the temperature of water. Find the increase in temperature of m mass of water in time t. Specific heat of water is s. Assume that there is no loss of energy through water surface.

If the rate constant of a reaction is 2xx10^(-3) per second. What is the order of a reaction ?

A radioactive nuclide is produced at a constant rate of alpha per second . It’s decay constant is lambda . If N_(0) be the no. of nuclei at time t=0 , then max. no. nuclei possible are :