Lead `.^(206)Pb` is found in a certain uranium ore due to disintegration of uranium. What is the age of uranium ore if its now contains 0.8gm of `.^(206)Pb` for each gram of `.^(238)U` given the half life of uranium `=4.5xx10^(9)` years.

The Uranium -238 decay series (also known as 4n+2 series. Can you tell why?) ends at a stable isotope .^(82)Pb^(206) . Lead -206 is found in a certain Uranium ore due to dissintegration of Uranium. (a) How many alpha and beta particles are emitted in the series decay of one ._(92)U^(238) nucleus into ._(82)Pb^(206) ? (b) what is the age of uranium ore if it now contains 8g of Pb^(206) for every 10g of U^(238) ? Hlaf life of U^(238) is 4.5 bilion year. [Take ln2=0.6930,ln(1.9243)=0.6546 ]

A sample of uranium mineral was found to contain Pb^(208) and U^(238) in the ratio of 0.008 : 1. Estimate the age of the mineral (half life of U^(238) is 4.51 xx 10^(9) years).

The radium and uranium atoms in a sample of uranium mineral are in the ratio of 12.8xx10^(6) . If half life period of radium is 1620 years , the half life period of uranium will be

A rock is 1.5 xx 10^(9) years old. The rock contains .^(238)U which disintegretes to form .^(236)U . Assume that there was no .^(206)Pb in the rock initially and it is the only stable product fromed by the decay. Calculate the ratio of number of nuclei of .^(238)U to that of .^(206)Pb in the rock. Half-life of .^(238)U is 4.5 xx 10^(9). years. (2^(1//3)=1.259) .

In an ore containing uranium, the ratio of ^238U to 206Pb nuclei is 3. Calculate the age of the ore, assuming that all the lead present in the ore is the final stable product of ^238U . Take the half-life of ^238U to be 4.5xx10^9 years.

In a smaple of rock, the ration .^(206)Pb to .^(238)U nulei is found to be 0.5. The age of the rock is (given half-life of U^(238) is 4.5 xx 10^(9) years).