Calculate the energy released by fission from `2 g` of `.^(235)._(92)U` in `kWh`. Given that the energy released per fission is `200 MeV`.

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

Calculate the energy released by the fission 1 g of .^(235)U in joule, given that the energy released per fission is 200 MeV . (Avogadro's number =6.023xx10^(23))

The enegry released per fission of .^(235)u is nearly

Calculate the energy released by fission of 1 g of ._(92)^(235)U , assuming that an energy of 200 MeV is released by fission of each atom of .^(235)U . (Avogardo constant is = 6.023 xx 10^(26) kg mol^(-1) )

What is the energy released by fassion of 1 g of U^(235) ? (Assume 200 Me V energy is liberated on fission of 1 nucleus)

Most of energy released in the fission is carried by

Calculate the amount of ""_(92)U^(235) required to release energy of 1 kWh. Given energy released during fission of one atom is 200 MeV.

The energy released by complete fission of one kilogram of ""^(235)U is equal to that released by complete burning of

Calculate the total energy released if 1.0 kg of .^(235)U undergoes fission, taking the disintergration energy per event to be Q=208 MeV (a more accurate value than the estimate given previously).

The energy released by fission of one U^(235) atom is 200 MeV. Calculate the energy released in kWh, when one gram of uranium undergoes fission.