IN a nuclear reactor, fission is produced in 1 g of `.^(235)U`
`(235.0349 am u)`. In assuming that `._(53)^(92)Kr (91.8673 am u)`
and `._(36)^(141)Ba (140.9139 am u)` are produced in all reactions and no energy is lost, calculate the total energy produced in killowatt. Given: `1 am u =931 MeV`.

Find the amount of energy released when 1 atom of Uranium ._(92)U^(235)(235.0439 "amu") undergoes fission by slow neturon (1.0087 "amu") and is splitted into Krypton ._(36)Kr^(92)(91.8973 "amu") and Barium ._(56)Br^(141)(140.9139 "amu") assuming no energy is lost. Hence find the enrgy in kWh , when 1g of it undergoes fission.

A neutron strikes a ""_(92)U^(235) nucleus and as a result ""_(36)Kr^(93) and ""_(56)Ba^(140) are produced with

1.00 kg of .^(235)U undergoes fission process. If energy released per event is 200 MeV , then the total energy released is

In the nuclear chain ractio: ._(92)^(235)U + ._(0)^(1)n rarr ._(56)^(141) Ba + ._(36)^(92)Kr + 3 ._(0)^(1)n + E The number fo neutrons and energy relaesed in nth step is:

When slow neutrons are incident on a target containing underset(92)overset(235).U , a possible fission reaction is underset(92)overset(235).U+underset(0)overset(1).nrarr underset(56)overset(141).Ba+underset(36)overset(92).Kr+3_(0)^(1)n Estimate the amount of energy released using the following data Given, mass of underset(92)overset(235).U=235.04 amu , mass of underset(0)overset(1).n=1.0087 amu , mass of underset(56)overset(141).Ba=140.91 amu , mass of underset(36)overset(92).Kr=91.926 amu , and energy equivalent to 1 amu=931 MeV.

Calculate the binding energy in MeV of Uranium 238 from the following data Mass of .^(1)H_(1) = 1.008142 am u , Mass of ._(0)n^(1) = 1.008982 am u Mass of ._(92)U^(238) = 238.124930 am u Also calculate the packing fraction.

The reaction ._(92)U^(235) + ._(0)n^(1) rarr ._(56)Ba^(140) + ._(36)Kr^(93) + 3 ._(0)n^(1) represents