Calcualte the excitation energy of the compound nuclei produced when
`{:(n+.^(235)U rarr.^(236)Uast),(n+.^(238)U rarr.^(239)Uast):}`
Given:
`{:(M(.^(235)U) = 235.0439 "amu"",",M(n) = 1.0087 "amu"","),(M(.^(238)U)238.0508 "amu,",M(.^(236)U) = 236.0456 "amu,"),(M(.^(239)U) = 239.0543 "amu",):}`.

Calcualte the excitation energy of the compound nuclei produced when Given: {:(M(.^(235)U) = 235.0439 "amu"",",M(n) = 1.0087 "amu"","),(M(.^(238)U)238.0508 "amu,",M(.^(236)U) = 236.0456 "amu,"),(M(.^(239)U) = 239.0543 "amu",):} .

Calculate the energy equivalent of 1 a.m.u. in MeV

""_(92)^(235)U, ""_(92)^(238)U and ""_(92)^(239)U are

Find the kinetic energy of emitted a-particles in the following nuclear reaction: ""_(94)Pu^(238) to ""_(92)U^(234) + ""_(2)He^(4) m(Pu^(238)) = 238.04954 amu m(U^(234)) = 234.04096 amu m(""_(2)He^(4)) = 4.002603 amu

Which one of the following is an artificial fuel for nuclear reactor? a. U^(238) b. Pu^(239) c. U^(235) d. Th^(232)

Compute the minimum kinetic energy of proton incident on .^(13)C nuclei at rest in the laboratory the will produce the endothermic reaction ^(13)C(p,n)^(13)N . Given masses are M(.^(13)C)=13.003355 amu, M(.^(1)H)=1.007825 amu m(n)=1.008665 amu, M(.^(13)N)=13.005738 amu

Calculate the binding energy per nucleon (B.E./nucleon) in the nuclei of ._(26)Fe^(56) . Given : mp[._(26)Fe^(56)]=55.934939 " amu",m[._(0)n^(1)]=1.00865 " amu" , m[._(1)"II"^(1)]=1.00782 " amu"

Consider one of the fission reactions of U^(235) by thernmal neutrons : ._(92)U^(235) + n rarr ._(38)Sr^(94) + ._(54)Ce^(140) + 2n The fission fragments are, however, not stable. They unaergo successive beta- decays unit ._(38)Sr^(94) becomes ._(40)Zr^(94) and ._(54)Xe^(140) becomes ._(58)Ce^(140) . Estimate the total energy released in the process. Is all that energy available as kinetic energy of the fission products (Zr and Ce)? You are given that m (U^(235)) = 255.0439 am u," " m_(n) = 1.00866 am u " " m(Zr^(94)) = 93.9065 am u, " " m(Ce^(140)) = 139.9055 am u

A slow neutron strikes a nucleus of ._(92)U^(235) splitting it into lighter nuclei of barium and krypton and releasing three neutrons. Write the corresponding nuclear reaction. Also calculate the energy released on this reaction Given m(._(92)U^(235))=235.043933 "amu" m(._(0)n^(1))=1.008665 amu m(._(56)Ba^(141))=140.917700 "amu" m(._(36)Kr^(92))=91.895400 amu