Calculate the ground state `Q` value of the induced fission raction in the equation
`n+._(92)^(235) Urarr._(92)^(236)Uastrarr._(40)^(99)Zr+._(52)^(134)Te+2n`
If the neutron is thermal. A thermal neutorn is in thermal equilibrium with its envitronmnet, it has an avergae kinetic energy given by `(3//2) kT`. Given :
`m(n) =1.0087 am u, M(.^(235)U)=235.0439) am u`,
`M(.^(99)Zr)=98.916 am u, M(.^(134)Te)=133.9115 am u`.

Calcualte the excitation energy of the compound nuclei produced when Given: {:(M(.^(235)U) = 235.0439 "amu"",",M(n) = 1.0087 "amu"","),(M(.^(238)U)238.0508 "amu,",M(.^(236)U) = 236.0456 "amu,"),(M(.^(239)U) = 239.0543 "amu",):} .

Consider one of the fission reactions of U^(235) by thernmal neutrons : ._(92)U^(235) + n rarr ._(38)Sr^(94) + ._(54)Ce^(140) + 2n The fission fragments are, however, not stable. They unaergo successive beta- decays unit ._(38)Sr^(94) becomes ._(40)Zr^(94) and ._(54)Xe^(140) becomes ._(58)Ce^(140) . Estimate the total energy released in the process. Is all that energy available as kinetic energy of the fission products (Zr and Ce)? You are given that m (U^(235)) = 255.0439 am u," " m_(n) = 1.00866 am u " " m(Zr^(94)) = 93.9065 am u, " " m(Ce^(140)) = 139.9055 am u

Show that ._(92)^(230)U does not decay by emitting a neutron or proton. Given: M(._(92)^(230)U)=230.033927 am u, M(._(92)^(230)U)=229.033496 am u , M(._(92)^(229)Pa)=229.032089 am u, M(n)=1.008665 am u m(p)=1.007825 am u .

U-235 is decayed by bombardment by neutron as according to the equation: ._(92)U^(235) + ._(0)n^(1) rarr ._(42)Mo^(98) + ._(54)Xe^(136) + x ._(-1)e^(0) + y ._(0)n^(1) Calculate the value of x and y and the energy released per uranium atom fragmented (neglect the mass of electron). Given masses (amu) U-235 = 235.044 , Xe = 135.907, Mo = 97.90, e = 5.5 xx 10^(-4), n = 1.0086 .

The ._(92)U^(235) absorbs a slow neturon (thermal neutron) & undergoes a fission represented by ._(92)U^(235)+._(0)n^(1)rarr._(92)U^(236)rarr._(56)Ba^(141)+_(36)Kr^(92)+3_(0)n^(1)+E . Calculate: The energy released when 1 g of ._(92)U^(235) undergoes complete fission in N if m=[N] then find (m-2)/(5) . [N] greatest integer Given ._(92)U^(235)=235.1175"amu (atom)" , ._(56)Ba^(141)=140.9577 "amu (atom)" , ._(36)r^(92)=91.9263 "amu(atom)" , ._(0)n^(1)=1.00898 "amu", 1 "amu"=931 MeV//C^(2)

A fusion reaction of the type given below ._(1)^(2)D+._(1)^(2)D rarr ._(1)^(3)T+._(1)^(1)p+DeltaE is most promissing for the production of power. Here D and T stand for deuterium and tritium, respectively. Calculate the mass of deuterium required per day for a power output of 10^(9) W . Assume the efficiency of the process to be 50% . Given : " "m(._(1)^(2)D)=2.01458 am u," "m(._(1)^(3)T)=3.01605 am u m(._(1)^(1) p)=1.00728 am u and 1 am u=930 MeV .

The ._(92)^(235)U absorbs a slow neutron (thermal neutron) & undergoes a fission represented by (i) The energy release E per fission. (ii) The energy release when 1g of ._(92)^(236)U undergoes complete fission. Given : ._(92)^(235)U = 235.1175 am u (atom), ._(56)^(141)Ba = 140.9577 am u (atom), ._(36)^(92)Kr = 91.9264 am u (atom), ._(0)^(1)n = 1.00898 am u .

A slow neutron strikes a nucleus of ._(92)U^(235) splitting it into lighter nuclei of barium and krypton and releasing three neutrons. Write the corresponding nuclear reaction. Also calculate the energy released on this reaction Given m(._(92)U^(235))=235.043933 "amu" m(._(0)n^(1))=1.008665 amu m(._(56)Ba^(141))=140.917700 "amu" m(._(36)Kr^(92))=91.895400 amu

Calculate the energy released in the following: ._(1)H^(2) + ._(1)H^(3) rarr ._(2)He^(4) + ._(0)n^(1) (Given masses : H^(2) = 2.014, H^(3) = 3.016, He = 4.003, n = 1.009 m_(u))

The minimum frequency of a gamma -ray that causes a deutron to disintegrate into a poton and a neutron is (m_(d)=2.0141 am u, m_p=1.0078 am u, m_n=1.0087 am u.) .