Show that `._(92)^(230)U` does not decay by emitting a neutron or proton. Given:
`M(._(92)^(230)U)=230.033927 am u, M(._(92)^(230)U)=229.033496 am u`,
`M(._(92)^(229)Pa)=229.032089 am u, M(n)=1.008665 am u`
`m(p)=1.007825 am u`.

Consider two arbitaray decay equation and mark the correct alternative s given below. (i) ._(92)^(230)U rarr n+._(92)^(229)U (ii) ._(92_^(230)U rarr P +._(91)^(229)Pa Given: M(._(92)^(230)U) =230.033927 u,M(._(92)^(229)U)=229.03349 u, m_(n)=1.008665u , M(._(91)^(229)Pa) =229.032089, m_p =1.007825, 1 am u =931.5 MeV .

Show that ""_(92)^(238)U can not spontaneously emit a proton. Given: ""_(92)^(238)U = 238.05079u, ""_(91)^(237)Pa = 237.05121u ""_(1)^(1)H = 1.00783u

Determine the number of protons and neutrons in ""_(92)U^(238) and ""_(90)Th^(234) .

""_(92)^(237)U undergoes beta -decay . The daughter nuclide belong to group

The ._(92)^(235)U absorbs a slow neutron (thermal neutron) & undergoes a fission represented by (i) The energy release E per fission. (ii) The energy release when 1g of ._(92)^(236)U undergoes complete fission. Given : ._(92)^(235)U = 235.1175 am u (atom), ._(56)^(141)Ba = 140.9577 am u (atom), ._(36)^(92)Kr = 91.9264 am u (atom), ._(0)^(1)n = 1.00898 am u .

Show that (._(26)^(55)Fe) may electron capture, but not beta^(+) decay. Masses given are M(._(26)^(55)Fe)=54.938298 am u , M(._(25)^(55)Mn)=54.938050 am u, m(e )=0.000549 am u .

Consider the following nuclear decay: (initially .^(236)U_(92) is at rest) ._(92)^(236)rarr._(90)^(232)ThrarrX Following atomic masses and conversion factor are provided ._(92)^(236)U=236.045 562 u , ._(90)^(232)Th=232.038054 u , ._(0)^(1)n=1.008665 ,. _(1)^(1)p=1.007277 u , ._(2)^(4)He=4.002603 u and 1 u=1.5xx10^(-10)J The amount of energy released in this decay is equal to: