Find the amount of energy produced in joules due to fission of 1 gram of uranium assuming that 0.1 percent of mass is transformed into energy.
Take 1amu=`1.66xx10^(-27)kg=931.5MeV`
Mass of uranium =235amu.
Avogadro number =`6.02xx10^(23)`

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

find the amount of energy produced in jaoules due to fission of 1 g of ""._(92)U^(235) assuming that 0.1% of mass is transormed into enengy ,Atomic mass of ""._(92)U^(235)=235 amu , Avogodro number N_(A)=6.023xx10^(23). Given that the energy released per fission is 200 MeV.

Show that energy equivalent of one atomic mass unit is nearly 933MeV . Take 1a m u=1.66xx10^(-27)kg

If one a.m.u.= 1.66xx10^(-27)kg , when is the mass of one atom of C^(12) ?

The average kinetic energy of one molecule of an ideal gas at 27^@C and 1 atm pressure is [Avogadro number N_A=6.023xx10^(23) ]

Find the rest mass energy of a proton in MeV. [m_(p) = 1.673 xx 10^(-27) kg]

The energy in MeV is released due to transformation of 1 kg mass completely into energy (c = 3 xx 10^8 m//s) .

Show that energy equivalent to atomic mass unit equals nearly 933 MeV of energy. Given 1 automic mass unit = 1.66xx10^(-27)kg

Find the half-life of uranium, given that 3.32 xx 10^(7) g radium is found per gram of uranium in old minerals. The atomic weights of uranium and radium are 238 and 226 and half-life of radium is 1600 years (Avogadro number is 6.023 xx 10^(23)//g -"atom" ).