Assuming that 200MeV of energy is released per fission of uranium atom, find the number of fission per second required to release one kilowatt power.

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 MW of power is :

The enegry released per fission of .^(235)u is nearly

If 200 MeV energy is released in the fission of a single U^235 nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given 1 eV = 1.6 xx 10^-19 J ).

Most of energy released in the fission is carried by

Assuming that about 200 MeV of energy is released per fission of ._(92)U^(235) nuceli, the mass of U^(235) consumed per day in a fission ractor of power 1 megawatt will be approximately .

The energy released by the fission of a single uranium nucleus is 200 MeV. The number of fission of uranium nucleus per second required to produce 16 MW of power is (Assume efficiency of the reactor is 50%)

If 200 MeV energy is released per fission of ._(92)U^(235) How many fissions must occur per second to produce a power of 1m W?